-21t+4(t-5)=48

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Solution for -21t+4(t-5)=48 equation: 



-21t+4(t-5)=48

We move all terms to the left:

-21t+4(t-5)-(48)=0

We multiply parentheses

-21t+4t-20-48=0

We add all the numbers together, and all the variables

-17t-68=0

We move all terms containing t to the left, all other terms to the right

-17t=68

t=68/-17

t=-4

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