-21=4(n-3)-(n-3)

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Solution for -21=4(n-3)-(n-3) equation: 



-21=4(n-3)-(n-3)

We move all terms to the left:

-21-(4(n-3)-(n-3))=0



We calculate terms in parentheses: -(4(n-3)-(n-3)), so:

4(n-3)-(n-3)

We multiply parentheses

4n-(n-3)-12

We get rid of parentheses

4n-n+3-12

We add all the numbers together, and all the variables

3n-9

Back to the equation:

-(3n-9)



We get rid of parentheses

-3n+9-21=0

We add all the numbers together, and all the variables

-3n-12=0

We move all terms containing n to the left, all other terms to the right

-3n=12

n=12/-3

n=-4

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