-21=3(n-99)

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Solution for -21=3(n-99) equation: 



-21=3(n-99)

We move all terms to the left:

-21-(3(n-99))=0



We calculate terms in parentheses: -(3(n-99)), so:

3(n-99)

We multiply parentheses

3n-297

Back to the equation:

-(3n-297)



We get rid of parentheses

-3n+297-21=0

We add all the numbers together, and all the variables

-3n+276=0

We move all terms containing n to the left, all other terms to the right

-3n=-276

n=-276/-3

n=+92

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