-20v+3v=11v2

Solution for -20v+3v=11v2 equation:

-20v+3v=11v^2

We move all terms to the left:

-20v+3v-(11v^2)=0

determiningTheFunctionDomain
-11v^2-20v+3v=0

We add all the numbers together, and all the variables

-11v^2-17v=0

a = -11; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·(-11)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*-11}=\frac{0}{-22}
=0
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*-11}=\frac{34}{-22}
=-1+6/11
$