-2/z+1/4z=7/z+10

Solution for -2/z+1/4z=7/z+10 equation:

D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

(1/4)*z-2/z = 7/z+10 // - 7/z+10

(1/4)*z-2/z-(7/z)-10 = 0

(1/4)*z-2/z-7*z^-1-10 = 0

1/4*z^1-9*z^-1-10*z^0 = 0

(1/4*z^2-10*z^1-9*z^0)/(z^1) = 0 // * z^2

z^1*(1/4*z^2-10*z^1-9*z^0) = 0

z^1

(1/4)*z^2-10*z-9 = 0

(1/4)*z^2-10*z-9 = 0

DELTA = (-10)^2-(-9*4*(1/4))

DELTA = 109

DELTA > 0

z = (109^(1/2)+10)/(2*(1/4)) or z = (10-109^(1/2))/(2*(1/4))

z = 2*(109^(1/2)+10) or z = 2*(10-109^(1/2))

z in { 2*(10-109^(1/2)), 2*(109^(1/2)+10)} 

z in { 2*(10-109^(1/2)), 2*(109^(1/2)+10) }