-2/w+6/2w=4

Solution for -2/w+6/2w=4 equation:

-2/w+6/2w=4

We move all terms to the left:

-2/w+6/2w-(4)=0


Domain of the equation: w!=0

w∈R



Domain of the equation: 2w!=0

w!=0/2

w!=0

w∈R


We calculate fractions


(-4w)/2w^2+6w/2w^2-4=0

We multiply all the terms by the denominator


(-4w)+6w-4*2w^2=0

We add all the numbers together, and all the variables

6w+(-4w)-4*2w^2=0

Wy multiply elements

-8w^2+6w+(-4w)=0

We get rid of parentheses

-8w^2+6w-4w=0

We add all the numbers together, and all the variables

-8w^2+2w=0

a = -8; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-8)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-8}=\frac{-4}{-16}
=1/4
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-8}=\frac{0}{-16}
=0
$