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-2/8x-9=4/3x-3
We move all terms to the left:
-2/8x-9-(4/3x-3)=0
Domain of the equation: 8x!=0
x!=0/8
x!=0
x∈R
Domain of the equation: 3x-3)!=0We get rid of parentheses
x∈R
-2/8x-4/3x+3-9=0
We calculate fractions
(-6x)/24x^2+(-32x)/24x^2+3-9=0
We add all the numbers together, and all the variables
(-6x)/24x^2+(-32x)/24x^2-6=0
We multiply all the terms by the denominator
(-6x)+(-32x)-6*24x^2=0
Wy multiply elements
-144x^2+(-6x)+(-32x)=0
We get rid of parentheses
-144x^2-6x-32x=0
We add all the numbers together, and all the variables
-144x^2-38x=0
a = -144; b = -38; c = 0;
Δ = b2-4ac
Δ = -382-4·(-144)·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1444}=38$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-38}{2*-144}=\frac{0}{-288} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+38}{2*-144}=\frac{76}{-288} =-19/72 $
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