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-2/8e-3/4e=-10
We move all terms to the left:
-2/8e-3/4e-(-10)=0
Domain of the equation: 8e!=0
e!=0/8
e!=0
e∈R
Domain of the equation: 4e!=0We add all the numbers together, and all the variables
e!=0/4
e!=0
e∈R
-2/8e-3/4e+10=0
We calculate fractions
(-8e)/32e^2+(-24e)/32e^2+10=0
We multiply all the terms by the denominator
(-8e)+(-24e)+10*32e^2=0
Wy multiply elements
320e^2+(-8e)+(-24e)=0
We get rid of parentheses
320e^2-8e-24e=0
We add all the numbers together, and all the variables
320e^2-32e=0
a = 320; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·320·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1024}=32$$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*320}=\frac{0}{640} =0 $$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*320}=\frac{64}{640} =1/10 $
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