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-2/5x+12x=-5
We move all terms to the left:
-2/5x+12x-(-5)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
12x-2/5x+5=0
We multiply all the terms by the denominator
12x*5x+5*5x-2=0
Wy multiply elements
60x^2+25x-2=0
a = 60; b = 25; c = -2;
Δ = b2-4ac
Δ = 252-4·60·(-2)
Δ = 1105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{1105}}{2*60}=\frac{-25-\sqrt{1105}}{120} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{1105}}{2*60}=\frac{-25+\sqrt{1105}}{120} $
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