-2/5(15-10z)=3z+2(z-5)

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Solution for -2/5(15-10z)=3z+2(z-5) equation: 



-2/5(15-10z)=3z+2(z-5)

We move all terms to the left:

-2/5(15-10z)-(3z+2(z-5))=0



Domain of the equation: 5(15-10z)!=0

z∈R



We add all the numbers together, and all the variables

-2/5(-10z+15)-(3z+2(z-5))=0

We multiply all the terms by the denominator


-((3z+2(z-5)))*5(-10z+15)-2=0



We calculate terms in parentheses: -((3z+2(z-5)))*5(-10z+15), so:

(3z+2(z-5)))*5(-10z+15

We add all the numbers together, and all the variables

-10z+(3z+2(z-5)))*5(+15

Back to the equation:

-(-10z+(3z+2(z-5)))*5(+15)



We add all the numbers together, and all the variables

-(-10z+(3z+2(z-5)))*515-2=0

We move all terms containing z to the left, all other terms to the right

-(-10z+(3z+2(z-5)))*515=2

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