-2/4(4z-2)=3z=7

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Solution for -2/4(4z-2)=3z=7 equation: 



-2/4(4z-2)=3z=7

We move all terms to the left:

-2/4(4z-2)-(3z)=0



Domain of the equation: 4(4z-2)!=0

z∈R



We add all the numbers together, and all the variables

-3z-2/4(4z-2)=0

We multiply all the terms by the denominator


-3z*4(4z-2)-2=0

Wy multiply elements

-12z^2(4-2=0

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