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-2/3x+2=4x-6
We move all terms to the left:
-2/3x+2-(4x-6)=0
Domain of the equation: 3x!=0We get rid of parentheses
x!=0/3
x!=0
x∈R
-2/3x-4x+6+2=0
We multiply all the terms by the denominator
-4x*3x+6*3x+2*3x-2=0
Wy multiply elements
-12x^2+18x+6x-2=0
We add all the numbers together, and all the variables
-12x^2+24x-2=0
a = -12; b = 24; c = -2;
Δ = b2-4ac
Δ = 242-4·(-12)·(-2)
Δ = 480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480}=\sqrt{16*30}=\sqrt{16}*\sqrt{30}=4\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-4\sqrt{30}}{2*-12}=\frac{-24-4\sqrt{30}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+4\sqrt{30}}{2*-12}=\frac{-24+4\sqrt{30}}{-24} $
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