-2/3b+12-4/3b=2

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Solution for -2/3b+12-4/3b=2 equation: 


b in (-oo:+oo)

(-2/3)*b-((4/3)*b)+12 = 2 // - 2

(-2/3)*b-((4/3)*b)-2+12 = 0

(-2/3)*b+(-4/3)*b-2+12 = 0

10-2*b = 0 // - 10

-2*b = -10 // : -2

b = -10/(-2)

b = 5

b = 5

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