-2/3(x-3)=1/3x

Solution for -2/3(x-3)=1/3x equation:

-2/3(x-3)=1/3x

We move all terms to the left:

-2/3(x-3)-(1/3x)=0


Domain of the equation: 3(x-3)!=0

x∈R



Domain of the equation: 3x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-2/3(x-3)-(+1/3x)=0

We get rid of parentheses

-2/3(x-3)-1/3x=0

We calculate fractions


(-6x)/(9x^2-27x)+(-3xx/(9x^2-27x)=0


We calculate terms in parentheses: +(-3xx/(9x^2-27x), so:

-3xx/(9x^2-27x

We multiply all the terms by the denominator


-3xx

Back to the equation:

+(-3xx)


We get rid of parentheses

(-6x)/(9x^2-27x)-3xx=0

We multiply all the terms by the denominator


(-6x)-3xx*(9x^2-27x)=0

We multiply parentheses

-27x^3+81x^2+(-6x)=0

We get rid of parentheses

-27x^3+81x^2-6x=0

We do not support expression: x^3