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-2.0=15t-4.905t^2
We move all terms to the left:
-2.0-(15t-4.905t^2)=0
We add all the numbers together, and all the variables
-(15t-4.905t^2)-2=0
We get rid of parentheses
4.905t^2-15t-2=0
a = 4.905; b = -15; c = -2;
Δ = b2-4ac
Δ = -152-4·4.905·(-2)
Δ = 264.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{264.24}}{2*4.905}=\frac{15-\sqrt{264.24}}{9.81} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{264.24}}{2*4.905}=\frac{15+\sqrt{264.24}}{9.81} $
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