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-2-2x=6x(2x+2)
We move all terms to the left:
-2-2x-(6x(2x+2))=0
We calculate terms in parentheses: -(6x(2x+2)), so:We get rid of parentheses
6x(2x+2)
We multiply parentheses
12x^2+12x
Back to the equation:
-(12x^2+12x)
-12x^2-2x-12x-2=0
We add all the numbers together, and all the variables
-12x^2-14x-2=0
a = -12; b = -14; c = -2;
Δ = b2-4ac
Δ = -142-4·(-12)·(-2)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-10}{2*-12}=\frac{4}{-24} =-1/6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+10}{2*-12}=\frac{24}{-24} =-1 $
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