-2-10x=(3x-7)(x+1)

Solution for -2-10x=(3x-7)(x+1) equation:

-2-10x=(3x-7)(x+1)

We move all terms to the left:

-2-10x-((3x-7)(x+1))=0

We multiply parentheses ..

-((+3x^2+3x-7x-7))-10x-2=0


We calculate terms in parentheses: -((+3x^2+3x-7x-7)), so:

(+3x^2+3x-7x-7)

We get rid of parentheses

3x^2+3x-7x-7

We add all the numbers together, and all the variables

3x^2-4x-7

Back to the equation:

-(3x^2-4x-7)


We add all the numbers together, and all the variables

-10x-(3x^2-4x-7)-2=0

We get rid of parentheses

-3x^2-10x+4x+7-2=0

We add all the numbers together, and all the variables

-3x^2-6x+5=0

a = -3; b = -6; c = +5;
Δ = b2-4ac
Δ = -62-4·(-3)·5
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{6}}{2*-3}=\frac{6-4\sqrt{6}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{6}}{2*-3}=\frac{6+4\sqrt{6}}{-6}
$