-2+(1+3x)-4=-8(x-1)

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Solution for -2+(1+3x)-4=-8(x-1) equation: 



-2+(1+3x)-4=-8(x-1)

We move all terms to the left:

-2+(1+3x)-4-(-8(x-1))=0

We add all the numbers together, and all the variables

(3x+1)-(-8(x-1))-2-4=0

We add all the numbers together, and all the variables

(3x+1)-(-8(x-1))-6=0

We get rid of parentheses

3x-(-8(x-1))+1-6=0



We calculate terms in parentheses: -(-8(x-1)), so:

-8(x-1)

We multiply parentheses

-8x+8

Back to the equation:

-(-8x+8)



We add all the numbers together, and all the variables

3x-(-8x+8)-5=0

We get rid of parentheses

3x+8x-8-5=0

We add all the numbers together, and all the variables

11x-13=0

We move all terms containing x to the left, all other terms to the right

11x=13

x=13/11

x=1+2/11

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