-2(z-6)=-7z+42

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Solution for -2(z-6)=-7z+42 equation: 



-2(z-6)=-7z+42

We move all terms to the left:

-2(z-6)-(-7z+42)=0

We multiply parentheses

-2z-(-7z+42)+12=0

We get rid of parentheses

-2z+7z-42+12=0

We add all the numbers together, and all the variables

5z-30=0

We move all terms containing z to the left, all other terms to the right

5z=30

z=30/5

z=6

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