-2(z+3)-z=-2-4(z+2)

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Solution for -2(z+3)-z=-2-4(z+2) equation: 



-2(z+3)-z=-2-4(z+2)

We move all terms to the left:

-2(z+3)-z-(-2-4(z+2))=0

We add all the numbers together, and all the variables

-1z-2(z+3)-(-2-4(z+2))=0

We multiply parentheses

-1z-2z-(-2-4(z+2))-6=0



We calculate terms in parentheses: -(-2-4(z+2)), so:

-2-4(z+2)

determiningTheFunctionDomain
-4(z+2)-2

We multiply parentheses

-4z-8-2

We add all the numbers together, and all the variables

-4z-10

Back to the equation:

-(-4z-10)



We add all the numbers together, and all the variables

-3z-(-4z-10)-6=0

We get rid of parentheses

-3z+4z+10-6=0

We add all the numbers together, and all the variables

z+4=0

We move all terms containing z to the left, all other terms to the right

z=-4

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