-2(z+3)-z-4=z-4(z+2)

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Solution for -2(z+3)-z-4=z-4(z+2) equation:


Simplifying
-2(z + 3) + -1z + -4 = z + -4(z + 2)

Reorder the terms:
-2(3 + z) + -1z + -4 = z + -4(z + 2)
(3 * -2 + z * -2) + -1z + -4 = z + -4(z + 2)
(-6 + -2z) + -1z + -4 = z + -4(z + 2)

Reorder the terms:
-6 + -4 + -2z + -1z = z + -4(z + 2)

Combine like terms: -6 + -4 = -10
-10 + -2z + -1z = z + -4(z + 2)

Combine like terms: -2z + -1z = -3z
-10 + -3z = z + -4(z + 2)

Reorder the terms:
-10 + -3z = z + -4(2 + z)
-10 + -3z = z + (2 * -4 + z * -4)
-10 + -3z = z + (-8 + -4z)

Reorder the terms:
-10 + -3z = -8 + z + -4z

Combine like terms: z + -4z = -3z
-10 + -3z = -8 + -3z

Add '3z' to each side of the equation.
-10 + -3z + 3z = -8 + -3z + 3z

Combine like terms: -3z + 3z = 0
-10 + 0 = -8 + -3z + 3z
-10 = -8 + -3z + 3z

Combine like terms: -3z + 3z = 0
-10 = -8 + 0
-10 = -8

Solving
-10 = -8

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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