-2(y-5y)+4=-6(2y-y)+6+13y

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Solution for -2(y-5y)+4=-6(2y-y)+6+13y equation: 



-2(y-5y)+4=-6(2y-y)+6+13y

We move all terms to the left:

-2(y-5y)+4-(-6(2y-y)+6+13y)=0

We add all the numbers together, and all the variables

-2(-4y)-(-6(+y)+6+13y)+4=0

We multiply parentheses

8y-(-6(+y)+6+13y)+4=0



We calculate terms in parentheses: -(-6(+y)+6+13y), so:

-6(+y)+6+13y

determiningTheFunctionDomain
-6(+y)+13y+6

We add all the numbers together, and all the variables

13y-6(+y)+6

We multiply parentheses

13y-6y+6

We add all the numbers together, and all the variables

7y+6

Back to the equation:

-(7y+6)



We get rid of parentheses

8y-7y-6+4=0

We add all the numbers together, and all the variables

y-2=0

We move all terms containing y to the left, all other terms to the right

y=2

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