-2(y-5)=2y+3-2(-3y-1)

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Solution for -2(y-5)=2y+3-2(-3y-1) equation: 



-2(y-5)=2y+3-2(-3y-1)

We move all terms to the left:

-2(y-5)-(2y+3-2(-3y-1))=0

We multiply parentheses

-2y-(2y+3-2(-3y-1))+10=0



We calculate terms in parentheses: -(2y+3-2(-3y-1)), so:

2y+3-2(-3y-1)

determiningTheFunctionDomain
2y-2(-3y-1)+3

We multiply parentheses

2y+6y+2+3

We add all the numbers together, and all the variables

8y+5

Back to the equation:

-(8y+5)



We get rid of parentheses

-2y-8y-5+10=0

We add all the numbers together, and all the variables

-10y+5=0

We move all terms containing y to the left, all other terms to the right

-10y=-5

y=-5/-10

y=1/2

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