-2(y-4)-(3y-2)=-2-(6y-2

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Solution for -2(y-4)-(3y-2)=-2-(6y-2 equation: 



-2(y-4)-(3y-2)=-2-(6y-2

We move all terms to the left:

-2(y-4)-(3y-2)-(-2-(6y-2)=0

We multiply parentheses

-2y-(3y-2)-(-2-(6y-2)+8=0

We get rid of parentheses

-2y-3y-(-2-(6y-2)+8+2=0

We add all the numbers together, and all the variables

-5y-(-2-(6y-2)+8+2=0

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