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-2(y-3)=6(2y+1)
We move all terms to the left:
-2(y-3)-(6(2y+1))=0
We multiply parentheses
-2y-(6(2y+1))+6=0
We calculate terms in parentheses: -(6(2y+1)), so:We get rid of parentheses
6(2y+1)
We multiply parentheses
12y+6
Back to the equation:
-(12y+6)
-2y-12y-6+6=0
We add all the numbers together, and all the variables
-14y=0
y=0/-14
y=0
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