-2(y-2)+(8y+5)=7(y+5)

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Solution for -2(y-2)+(8y+5)=7(y+5) equation: 



-2(y-2)+(8y+5)=7(y+5)

We move all terms to the left:

-2(y-2)+(8y+5)-(7(y+5))=0

We multiply parentheses

-2y+(8y+5)-(7(y+5))+4=0

We get rid of parentheses

-2y+8y-(7(y+5))+5+4=0



We calculate terms in parentheses: -(7(y+5)), so:

7(y+5)

We multiply parentheses

7y+35

Back to the equation:

-(7y+35)



We add all the numbers together, and all the variables

6y-(7y+35)+9=0

We get rid of parentheses

6y-7y-35+9=0

We add all the numbers together, and all the variables

-1y-26=0

We move all terms containing y to the left, all other terms to the right

-y=26

y=26/-1

y=-26

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