-2(y+4)=8y-3+2(4y+5)

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Solution for -2(y+4)=8y-3+2(4y+5) equation: 



-2(y+4)=8y-3+2(4y+5)

We move all terms to the left:

-2(y+4)-(8y-3+2(4y+5))=0

We multiply parentheses

-2y-(8y-3+2(4y+5))-8=0



We calculate terms in parentheses: -(8y-3+2(4y+5)), so:

8y-3+2(4y+5)

determiningTheFunctionDomain
8y+2(4y+5)-3

We multiply parentheses

8y+8y+10-3

We add all the numbers together, and all the variables

16y+7

Back to the equation:

-(16y+7)



We get rid of parentheses

-2y-16y-7-8=0

We add all the numbers together, and all the variables

-18y-15=0

We move all terms containing y to the left, all other terms to the right

-18y=15

y=15/-18

y=-5/6

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