-2(y+4)=2y-6+2(3y+1)

Solution for -2(y+4)=2y-6+2(3y+1) equation:

-2(y+4)=2y-6+2(3y+1)

We move all terms to the left:

-2(y+4)-(2y-6+2(3y+1))=0

We multiply parentheses

-2y-(2y-6+2(3y+1))-8=0


We calculate terms in parentheses: -(2y-6+2(3y+1)), so:

2y-6+2(3y+1)

determiningTheFunctionDomain
2y+2(3y+1)-6

We multiply parentheses

2y+6y+2-6

We add all the numbers together, and all the variables

8y-4

Back to the equation:

-(8y-4)


We get rid of parentheses

-2y-8y+4-8=0

We add all the numbers together, and all the variables

-10y-4=0

We move all terms containing y to the left, all other terms to the right

-10y=4

y=4/-10

y=-2/5