-2(y+1)+5=3(y+1)-2

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Solution for -2(y+1)+5=3(y+1)-2 equation: 



-2(y+1)+5=3(y+1)-2

We move all terms to the left:

-2(y+1)+5-(3(y+1)-2)=0

We multiply parentheses

-2y-(3(y+1)-2)-2+5=0



We calculate terms in parentheses: -(3(y+1)-2), so:

3(y+1)-2

We multiply parentheses

3y+3-2

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We add all the numbers together, and all the variables

-2y-(3y+1)+3=0

We get rid of parentheses

-2y-3y-1+3=0

We add all the numbers together, and all the variables

-5y+2=0

We move all terms containing y to the left, all other terms to the right

-5y=-2

y=-2/-5

y=2/5

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