-2(x-5)+10=-3(x+2)=x

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Solution for -2(x-5)+10=-3(x+2)=x equation: 



-2(x-5)+10=-3(x+2)=x

We move all terms to the left:

-2(x-5)+10-(-3(x+2))=0

We multiply parentheses

-2x-(-3(x+2))+10+10=0



We calculate terms in parentheses: -(-3(x+2)), so:

-3(x+2)

We multiply parentheses

-3x-6

Back to the equation:

-(-3x-6)



We add all the numbers together, and all the variables

-2x-(-3x-6)+20=0

We get rid of parentheses

-2x+3x+6+20=0

We add all the numbers together, and all the variables

x+26=0

We move all terms containing x to the left, all other terms to the right

x=-26

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