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-2(x-4)=4x+3(2-2x)
We move all terms to the left:
-2(x-4)-(4x+3(2-2x))=0
We add all the numbers together, and all the variables
-2(x-4)-(4x+3(-2x+2))=0
We multiply parentheses
-2x-(4x+3(-2x+2))+8=0
We calculate terms in parentheses: -(4x+3(-2x+2)), so:We get rid of parentheses
4x+3(-2x+2)
We multiply parentheses
4x-6x+6
We add all the numbers together, and all the variables
-2x+6
Back to the equation:
-(-2x+6)
-2x+2x-6+8=0
We add all the numbers together, and all the variables
2!=0
There is no solution for this equation
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