-2(x-4)-3(4-x)=6(x+4)+6+7(x+2)

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Solution for -2(x-4)-3(4-x)=6(x+4)+6+7(x+2) equation: 



-2(x-4)-3(4-x)=6(x+4)+6+7(x+2)

We move all terms to the left:

-2(x-4)-3(4-x)-(6(x+4)+6+7(x+2))=0

We add all the numbers together, and all the variables

-2(x-4)-3(-1x+4)-(6(x+4)+6+7(x+2))=0

We multiply parentheses

-2x+3x-(6(x+4)+6+7(x+2))+8-12=0



We calculate terms in parentheses: -(6(x+4)+6+7(x+2)), so:

6(x+4)+6+7(x+2)

determiningTheFunctionDomain
6(x+4)+7(x+2)+6

We multiply parentheses

6x+7x+24+14+6

We add all the numbers together, and all the variables

13x+44

Back to the equation:

-(13x+44)



We add all the numbers together, and all the variables

x-(13x+44)-4=0

We get rid of parentheses

x-13x-44-4=0

We add all the numbers together, and all the variables

-12x-48=0

We move all terms containing x to the left, all other terms to the right

-12x=48

x=48/-12

x=-4

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