-2(x-4)+6=3(x-2)

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Solution for -2(x-4)+6=3(x-2) equation: 



-2(x-4)+6=3(x-2)

We move all terms to the left:

-2(x-4)+6-(3(x-2))=0

We multiply parentheses

-2x-(3(x-2))+8+6=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

-2x-(3x-6)+14=0

We get rid of parentheses

-2x-3x+6+14=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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