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-2(x-3)-4=3x-5(x-1)
We move all terms to the left:
-2(x-3)-4-(3x-5(x-1))=0
We multiply parentheses
-2x-(3x-5(x-1))+6-4=0
We calculate terms in parentheses: -(3x-5(x-1)), so:We add all the numbers together, and all the variables
3x-5(x-1)
We multiply parentheses
3x-5x+5
We add all the numbers together, and all the variables
-2x+5
Back to the equation:
-(-2x+5)
-2x-(-2x+5)+2=0
We get rid of parentheses
-2x+2x-5+2=0
We add all the numbers together, and all the variables
-3!=0
There is no solution for this equation
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