-2(x-3)+5x=6(x-2)

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Solution for -2(x-3)+5x=6(x-2) equation: 



-2(x-3)+5x=6(x-2)

We move all terms to the left:

-2(x-3)+5x-(6(x-2))=0

We add all the numbers together, and all the variables

5x-2(x-3)-(6(x-2))=0

We multiply parentheses

5x-2x-(6(x-2))+6=0



We calculate terms in parentheses: -(6(x-2)), so:

6(x-2)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We add all the numbers together, and all the variables

3x-(6x-12)+6=0

We get rid of parentheses

3x-6x+12+6=0

We add all the numbers together, and all the variables

-3x+18=0

We move all terms containing x to the left, all other terms to the right

-3x=-18

x=-18/-3

x=+6

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