-2(x-3)+1(x-4)=2

Solution for -2(x-3)+1(x-4)=2 equation:

Simplifying
-2(x + -3) + 1(x + -4) = 2

Reorder the terms:
-2(-3 + x) + 1(x + -4) = 2
(-3 * -2 + x * -2) + 1(x + -4) = 2
(6 + -2x) + 1(x + -4) = 2

Reorder the terms:
6 + -2x + 1(-4 + x) = 2
6 + -2x + (-4 * 1 + x * 1) = 2
6 + -2x + (-4 + 1x) = 2

Reorder the terms:
6 + -4 + -2x + 1x = 2

Combine like terms: 6 + -4 = 2
2 + -2x + 1x = 2

Combine like terms: -2x + 1x = -1x
2 + -1x = 2

Add '-2' to each side of the equation.
2 + -2 + -1x = 2 + -2

Combine like terms: 2 + -2 = 0
0 + -1x = 2 + -2
-1x = 2 + -2

Combine like terms: 2 + -2 = 0
-1x = 0

Solving
-1x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-1'.
x = 0

Simplifying
x = 0