-2(x-2)+4x=3(x+4)+13

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Solution for -2(x-2)+4x=3(x+4)+13 equation: 



-2(x-2)+4x=3(x+4)+13

We move all terms to the left:

-2(x-2)+4x-(3(x+4)+13)=0

We add all the numbers together, and all the variables

4x-2(x-2)-(3(x+4)+13)=0

We multiply parentheses

4x-2x-(3(x+4)+13)+4=0



We calculate terms in parentheses: -(3(x+4)+13), so:

3(x+4)+13

We multiply parentheses

3x+12+13

We add all the numbers together, and all the variables

3x+25

Back to the equation:

-(3x+25)



We add all the numbers together, and all the variables

2x-(3x+25)+4=0

We get rid of parentheses

2x-3x-25+4=0

We add all the numbers together, and all the variables

-1x-21=0

We move all terms containing x to the left, all other terms to the right

-x=21

x=21/-1

x=-21

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