-2(x-2)+4x=-3(x+4)+13

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Solution for -2(x-2)+4x=-3(x+4)+13 equation: 



-2(x-2)+4x=-3(x+4)+13

We move all terms to the left:

-2(x-2)+4x-(-3(x+4)+13)=0

We add all the numbers together, and all the variables

4x-2(x-2)-(-3(x+4)+13)=0

We multiply parentheses

4x-2x-(-3(x+4)+13)+4=0



We calculate terms in parentheses: -(-3(x+4)+13), so:

-3(x+4)+13

We multiply parentheses

-3x-12+13

We add all the numbers together, and all the variables

-3x+1

Back to the equation:

-(-3x+1)



We add all the numbers together, and all the variables

2x-(-3x+1)+4=0

We get rid of parentheses

2x+3x-1+4=0

We add all the numbers together, and all the variables

5x+3=0

We move all terms containing x to the left, all other terms to the right

5x=-3

x=-3/5

x=-3/5

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