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-2(x+5)=x-2(2+x)
We move all terms to the left:
-2(x+5)-(x-2(2+x))=0
We add all the numbers together, and all the variables
-2(x+5)-(x-2(x+2))=0
We multiply parentheses
-2x-(x-2(x+2))-10=0
We calculate terms in parentheses: -(x-2(x+2)), so:We get rid of parentheses
x-2(x+2)
We multiply parentheses
x-2x-4
We add all the numbers together, and all the variables
-1x-4
Back to the equation:
-(-1x-4)
-2x+1x+4-10=0
We add all the numbers together, and all the variables
-1x-6=0
We move all terms containing x to the left, all other terms to the right
-x=6
x=6/-1
x=-6
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