-2(x+3)4x-4=-14

Solution for -2(x+3)4x-4=-14 equation:

-2(x+3)4x-4=-14

We move all terms to the left:

-2(x+3)4x-4-(-14)=0

We add all the numbers together, and all the variables

-2(x+3)4x+10=0

We multiply parentheses

-8x^2-24x+10=0

a = -8; b = -24; c = +10;
Δ = b2-4ac
Δ = -242-4·(-8)·10
Δ = 896
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{896}=\sqrt{64*14}=\sqrt{64}*\sqrt{14}=8\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-8\sqrt{14}}{2*-8}=\frac{24-8\sqrt{14}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+8\sqrt{14}}{2*-8}=\frac{24+8\sqrt{14}}{-16}
$