-2(x+1)+2=3(x-2)+1

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Solution for -2(x+1)+2=3(x-2)+1 equation: 



-2(x+1)+2=3(x-2)+1

We move all terms to the left:

-2(x+1)+2-(3(x-2)+1)=0

We multiply parentheses

-2x-(3(x-2)+1)-2+2=0



We calculate terms in parentheses: -(3(x-2)+1), so:

3(x-2)+1

We multiply parentheses

3x-6+1

We add all the numbers together, and all the variables

3x-5

Back to the equation:

-(3x-5)



We add all the numbers together, and all the variables

-2x-(3x-5)=0

We get rid of parentheses

-2x-3x+5=0

We add all the numbers together, and all the variables

-5x+5=0

We move all terms containing x to the left, all other terms to the right

-5x=-5

x=-5/-5

x=1

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