-2(v+5)=6v-9+2(2v+1)

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Solution for -2(v+5)=6v-9+2(2v+1) equation: 



-2(v+5)=6v-9+2(2v+1)

We move all terms to the left:

-2(v+5)-(6v-9+2(2v+1))=0

We multiply parentheses

-2v-(6v-9+2(2v+1))-10=0



We calculate terms in parentheses: -(6v-9+2(2v+1)), so:

6v-9+2(2v+1)

determiningTheFunctionDomain
6v+2(2v+1)-9

We multiply parentheses

6v+4v+2-9

We add all the numbers together, and all the variables

10v-7

Back to the equation:

-(10v-7)



We get rid of parentheses

-2v-10v+7-10=0

We add all the numbers together, and all the variables

-12v-3=0

We move all terms containing v to the left, all other terms to the right

-12v=3

v=3/-12

v=-1/4

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