-2(v+5)=3v-2+2(5v+5)

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Solution for -2(v+5)=3v-2+2(5v+5) equation: 



-2(v+5)=3v-2+2(5v+5)

We move all terms to the left:

-2(v+5)-(3v-2+2(5v+5))=0

We multiply parentheses

-2v-(3v-2+2(5v+5))-10=0



We calculate terms in parentheses: -(3v-2+2(5v+5)), so:

3v-2+2(5v+5)

determiningTheFunctionDomain
3v+2(5v+5)-2

We multiply parentheses

3v+10v+10-2

We add all the numbers together, and all the variables

13v+8

Back to the equation:

-(13v+8)



We get rid of parentheses

-2v-13v-8-10=0

We add all the numbers together, and all the variables

-15v-18=0

We move all terms containing v to the left, all other terms to the right

-15v=18

v=18/-15

v=-1+1/5

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