-2(v+2)=2v-4+3(2v+5)

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Solution for -2(v+2)=2v-4+3(2v+5) equation: 



-2(v+2)=2v-4+3(2v+5)

We move all terms to the left:

-2(v+2)-(2v-4+3(2v+5))=0

We multiply parentheses

-2v-(2v-4+3(2v+5))-4=0



We calculate terms in parentheses: -(2v-4+3(2v+5)), so:

2v-4+3(2v+5)

determiningTheFunctionDomain
2v+3(2v+5)-4

We multiply parentheses

2v+6v+15-4

We add all the numbers together, and all the variables

8v+11

Back to the equation:

-(8v+11)



We get rid of parentheses

-2v-8v-11-4=0

We add all the numbers together, and all the variables

-10v-15=0

We move all terms containing v to the left, all other terms to the right

-10v=15

v=15/-10

v=-1+1/2

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