-2(v+2)=2v-32

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Solution for -2(v+2)=2v-32 equation: 



-2(v+2)=2v-32

We move all terms to the left:

-2(v+2)-(2v-32)=0

We multiply parentheses

-2v-(2v-32)-4=0

We get rid of parentheses

-2v-2v+32-4=0

We add all the numbers together, and all the variables

-4v+28=0

We move all terms containing v to the left, all other terms to the right

-4v=-28

v=-28/-4

v=+7

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