-2(u+8)=4u-5+2(2u+2)

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Solution for -2(u+8)=4u-5+2(2u+2) equation: 



-2(u+8)=4u-5+2(2u+2)

We move all terms to the left:

-2(u+8)-(4u-5+2(2u+2))=0

We multiply parentheses

-2u-(4u-5+2(2u+2))-16=0



We calculate terms in parentheses: -(4u-5+2(2u+2)), so:

4u-5+2(2u+2)

determiningTheFunctionDomain
4u+2(2u+2)-5

We multiply parentheses

4u+4u+4-5

We add all the numbers together, and all the variables

8u-1

Back to the equation:

-(8u-1)



We get rid of parentheses

-2u-8u+1-16=0

We add all the numbers together, and all the variables

-10u-15=0

We move all terms containing u to the left, all other terms to the right

-10u=15

u=15/-10

u=-1+1/2

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