-2(u+2)=6u-9+2(2u+1)

Solution for -2(u+2)=6u-9+2(2u+1) equation:

-2(u+2)=6u-9+2(2u+1)

We move all terms to the left:

-2(u+2)-(6u-9+2(2u+1))=0

We multiply parentheses

-2u-(6u-9+2(2u+1))-4=0


We calculate terms in parentheses: -(6u-9+2(2u+1)), so:

6u-9+2(2u+1)

determiningTheFunctionDomain
6u+2(2u+1)-9

We multiply parentheses

6u+4u+2-9

We add all the numbers together, and all the variables

10u-7

Back to the equation:

-(10u-7)


We get rid of parentheses

-2u-10u+7-4=0

We add all the numbers together, and all the variables

-12u+3=0

We move all terms containing u to the left, all other terms to the right

-12u=-3

u=-3/-12

u=1/4