-2(u+2)=4u-4+2(5u+6)

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Solution for -2(u+2)=4u-4+2(5u+6) equation: 



-2(u+2)=4u-4+2(5u+6)

We move all terms to the left:

-2(u+2)-(4u-4+2(5u+6))=0

We multiply parentheses

-2u-(4u-4+2(5u+6))-4=0



We calculate terms in parentheses: -(4u-4+2(5u+6)), so:

4u-4+2(5u+6)

determiningTheFunctionDomain
4u+2(5u+6)-4

We multiply parentheses

4u+10u+12-4

We add all the numbers together, and all the variables

14u+8

Back to the equation:

-(14u+8)



We get rid of parentheses

-2u-14u-8-4=0

We add all the numbers together, and all the variables

-16u-12=0

We move all terms containing u to the left, all other terms to the right

-16u=12

u=12/-16

u=-3/4

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