-2(u+2)=3u-6+2(5u+6)

Solution for -2(u+2)=3u-6+2(5u+6) equation:

-2(u+2)=3u-6+2(5u+6)

We move all terms to the left:

-2(u+2)-(3u-6+2(5u+6))=0

We multiply parentheses

-2u-(3u-6+2(5u+6))-4=0


We calculate terms in parentheses: -(3u-6+2(5u+6)), so:

3u-6+2(5u+6)

determiningTheFunctionDomain
3u+2(5u+6)-6

We multiply parentheses

3u+10u+12-6

We add all the numbers together, and all the variables

13u+6

Back to the equation:

-(13u+6)


We get rid of parentheses

-2u-13u-6-4=0

We add all the numbers together, and all the variables

-15u-10=0

We move all terms containing u to the left, all other terms to the right

-15u=10

u=10/-15

u=-2/3