-2(u+1)=2u-5+2(7u+6)

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Solution for -2(u+1)=2u-5+2(7u+6) equation: 



-2(u+1)=2u-5+2(7u+6)

We move all terms to the left:

-2(u+1)-(2u-5+2(7u+6))=0

We multiply parentheses

-2u-(2u-5+2(7u+6))-2=0



We calculate terms in parentheses: -(2u-5+2(7u+6)), so:

2u-5+2(7u+6)

determiningTheFunctionDomain
2u+2(7u+6)-5

We multiply parentheses

2u+14u+12-5

We add all the numbers together, and all the variables

16u+7

Back to the equation:

-(16u+7)



We get rid of parentheses

-2u-16u-7-2=0

We add all the numbers together, and all the variables

-18u-9=0

We move all terms containing u to the left, all other terms to the right

-18u=9

u=9/-18

u=-1/2

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